एक पतली खोखली शंकु रेखा का गुरुत्वाकर्षण केन्द्र सममित के अक्ष पर ______ऊँचाई पर होता है। 

This question was previously asked in
SSC JE CE Previous Year Paper 15 (Held On: SSC JE CE 4 March 2017 Morning)
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  1. आधार से ऊपर कुल ऊँचाई की आधी
  2. आधार से ऊपर कुल ऊँचाई की एक तिहाई
  3. आधार से ऊपर कुल ऊँचाई की एक चौथाई

  4. इनमें से कोई नहीं

Answer (Detailed Solution Below)

Option 2 : आधार से ऊपर कुल ऊँचाई की एक तिहाई
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Detailed Solution

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विभिन्न समतल क्षेत्रों के लिए गुरुत्वाकर्षण केन्द्र

1) त्रिकोण

F4 N.M Madhu 12.03.20 D8

 

2) त्रिज्या ‘R’ की अर्ध वृत्त

F4 N.M Madhu 12.03.20 D9

 

3) खोखला शंकु (समकोण)

F4 N.M Madhu 12.03.20 D10

 

4) समलम्ब

F4 N.M Madhu 12.03.20 D11

 

\(\bar y = \frac{{ga + 6}}{{\left( {a + 6} \right)}}\;\left( {\frac{4}{3}} \right)\)

5) ज्या तरंगF4 N.M Madhu 12.03.20 D12

6) 4th डिग्री का  वक्र

F4 N.M Madhu 12.03.20 D13

 

\(\bar x = \left( {\frac{{6\left( {N + 1} \right)}}{{2\left( {N + 2} \right)}}} \right)\)

\(\bar y = \left( {\frac{{hN}}{{ZN + 1}}} \right)\)

Important Points

  1. Centre of gravity of a thin hollow cone = 1/3
  2. Centre of gravity of a solid cone = 1/4
Latest SSC JE CE Updates

Last updated on May 28, 2025

-> SSC JE notification 2025 for Civil Engineering will be released on June 30. 

-> Candidates can fill the SSC JE CE application from June 30 to July 21.

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