Question
Download Solution PDFयदि Δ ABC~Δ FDE इस प्रकार है कि AB = 9 सेमी, AC = 11 सेमी, DF = 16 सेमी तथा DE = 12 सेमी है, तो BC की लम्बाई क्या होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AB = 9 सेमी, AC = 11 सेमी, DF = 16 सेमी तथा DE = 12 सेमी
प्रयुक्त अवधारणा:
जब दो त्रिभुज समरूप होते हैं, तो उनके संगत कोण बराबर होते हैं और उनकी संगत भुजाएँ समानुपाती होती हैं।
गणना:
चूँकि ΔABC ~ ΔFDE
इसलिए, AB/DF = BC/DE = AC/FE
अब,
AB/DF = BC/DE
⇒ 9/16 = BC/12
⇒ BC = (9 × 12)/16
⇒ BC = 27/4
⇒ BC =
∴ BC की लम्बाई
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