समलम्ब चतुर्भुज ABCD में, ∠BAE = 30°, ∠CDF = 45°, BC = 6 सेमी. और AB = 12 सेमी. हो, तो ABCD का क्षेत्रफल ज्ञात कीजिए।

Assign 7 Pankaj 28Mar 25Q HinRev Harish images Q15

  1. 6(3 + √3) वर्ग सेमी.
  2. 12(3 + √3) वर्ग सेमी.
  3. 18(3 + √3) वर्ग सेमी.
  4. 24(3 + √3) वर्ग सेमी.

Answer (Detailed Solution Below)

Option 3 : 18(3 + √3) वर्ग सेमी.
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Detailed Solution

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ΔABE में,

⇒ cos30° = AE/AB

⇒ AE = 6√3 सेमी.

⇒ sin30° = BE/AB

⇒ BE = 6 cm

ΔCFD में,

⇒ tan45° = CF/FD

⇒ FD = 6 सेमी. [∵ BE = CF = 6 सेमी.]

⇒ AD = AE + EF + FD

⇒ AD = 6√3 + 6 + 6 सेमी

⇒ AD = 12 + 6√3 सेमी

⇒ समलम्ब चतुर्भुज का क्षेत्रफल = 1/2 × (समानांतर भुजाओं का योग) × ऊंचाई

⇒ समलम्ब चतुर्भुज का क्षेत्रफल = 1/2 × (BC + AD) × BE

∴ समलम्ब चतुर्भुज का क्षेत्रफल = 1/2 × (12 + 6√3 + 6) × 6 = 18(3 + √3) वर्ग सेमी.
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