Question
Download Solution PDFசரிவகம் ABCD இல், ∠BAE = 30°, ∠CDF = 45°, BC = 6 செமீ மற்றும் AB = 12 செ.மீ. ABCD இன் பரப்பளவைக் கண்டறியவும்.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFΔABE இல்,
⇒ cos30° = AE/AB
⇒ AE = 6√3 செ.மீ
⇒ sin30° = BE/AB
⇒ BE = 6 செ.மீ
ΔCFD இல்,
⇒ tan45° = CF/FD
⇒ FD = 6 செமீ [∵ BE = CF = 6 செமீ]
⇒ AD = AE + EF + FD
⇒ AD = 6√3 + 6 + 6 செ.மீ
⇒ AD = 12 + 6√3 செ.மீ
⇒ சரிவகத்தின் பரப்பளவு = 1/2 x (இணை பக்கங்களின் கூட்டுத்தொகை) x உயரம்
⇒ சரிவகத்தின் பரப்பளவு = 1/2 x (BC + AD) x BE
∴ சரிவகத்தின் பரப்பளவு = 1/2 x (12 + 6√3 + 6) x 6 = 18(3 + √3) செமீ2Last updated on Jun 13, 2025
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