Question
Download Solution PDFΔABC में, ∠A ∶ ∠B ∶ ∠C = 2 ∶ 3 ∶ 4 है। यदि BA के समांतर एक रेखा CD खींची जाती है, तब ∠ACD का मान कितना होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFमाना कि कोण हैं- A=2x, ∠B=3x, ∠C=4x
त्रिभुज के सभी कोणों का योगफल 180° होता है।
⇒ 2x + 3x + 4x = 180°
⇒ 9x = 180°
⇒ x = 20°
इसलिए, ∠A = 2 × 20° = 40°
∠B = 3 × 20° = 60°
∠C = 4 × 20° = 80°
दिया गया है: AB || CD, इसलिए, AC एक तिर्यक रेखा के रूप में कार्य करती है।
आरेख इस प्रकार है,
∠BAC = ∠ACD
अर्थात् ∠ACD = 40°
अतः, सही उत्तर "40°" है।
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