Question
Download Solution PDFΔABCలో ∠A ∶ ∠B ∶ ∠C = 2 ∶ 3 ∶ 4. BAకి సమాంతరంగా గీసిన రేఖ CD, అప్పుడు ∠ACD కనుగొనండి?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFకోణాలు ∠A=2x, ∠B=3x, ∠C=4x అనుకుందాం
త్రిభుజం యొక్క అన్ని కోణాల మొత్తం 180°.
⇒ 2x + 3x + 4x = 180°
⇒ 9x = 180°
⇒ x = 20°
కాబట్టి, ∠A = 2 × 20° = 40°
∠B = 3 × 20° = 60°
∠C = 4 × 20° = 80°
ఇచ్చిన AB || CD, కాబట్టి, AC ఒక విలోమ రేఖగా పనిచేస్తుంది.
రేఖాచిత్రం ఏమిటంటే,
∠BAC = ∠ACD
అనగా ∠ACD = 40°
కాబట్టి, సరైన సమాధానం "40°".
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