दो द्विध्रुव जिनके द्विध्रुव आघूर्ण -5az nC-m और 9az nC-m हैं, क्रमशः बिंदुओं (0, 0, -2) और (0, 0, 3) पर स्थित हैं। मूल बिंदु पर विभव क्या है?

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UPSC ESE (Prelims) Electronics and Telecommunication Engineering 19 Feb 2023 Official Paper
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  1. -24.25 V
  2. -22.25 V
  3. -20.25 V
  4. -18.25 V

Answer (Detailed Solution Below)

Option 3 : -20.25 V
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दोनों द्विध्रुवों के कारण मूल बिंदु पर विद्युत विभव ज्ञात करने के लिए।

जहाँ p1 और p2 द्विध्रुव आघूर्ण हैं, r1 और r2 ब्याज के बिंदु से द्विध्रुवों की दूरी हैं।

P1 = (0,0,-2), -5az nC-m

p2 = (0,0,3), 9az nC-m

P0 = (0,0,0) (V = V1 + V2)

विभव (V) = \(\frac{KP\cdot a_r}{r^2} \)

K = \(\frac{1}{4\pi\varepsilon_0}= 9\times10^9\)

\(V_1 = \frac{9\times 10^9 \times(-5a_z\times10^-9)\cdot a_z}{2^2}\)

\(V_1 = -\frac{45}{4}\)

\(V_2 = \frac{9\times 10^9 \times(9a_z\times10^-9)\cdot a_z}{3^2}\)

V2 = 9

V = V1 + V2 = \(-\frac{45}{4}+9 = -2.25V\)

यहाँ, विकल्प 3 सही है।

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