Question
Download Solution PDFsin4 θ + cos4 θ - 2sin2 θ cos2θ का न्यूनतम मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
त्रिकोणमितीय व्यंजक इस प्रकार है
sin4 θ + cos4 θ - 2sin2 θ cos2θ
प्रयुक्त अवधारणा:
-1 ≤ cosθ ≤ 1, 0 ≤ cos2θ ≤ 1
-1 ≤ sinθ ≤ 1, 0 ≤ sin2θ ≤ 1
cos2 θ - sin2 θ = cos 2θ
गणना:
हमारे पास है sin4 θ + cos4 θ - 2sin2 θ cos2θ
⇒ (cos2 θ)2 + (sin2 θ)2 - 2. sin2 θ. cos2θ
सूत्र के उपयोग से a2 + b2 - 2ab = (a - b)2
⇒ (cos2 θ - sin2 θ)2
⇒ (cos 2θ)2
⇒ cos2 2θ
प्रयुक्त अवधारणा के अनुसार
cos θ का न्यूनतम मान 0 है।
∴ cos2 2θ का न्यूनतम मान 0 है।
Last updated on May 29, 2025
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