Question
Download Solution PDFIf (3a + 6b + c + 2d) × (3a - 6b - c + 2d) = (3a - 6b + c - 2d) × (3a + 6b - c - 2d), then which one of the following is correct?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept Used:
If \(\frac{a+b}{a-b}\) = \(\frac{c+d}{c-d}\) then \(\frac{a}{b}\) = \(\frac{c}{d}\)
Calculation:
(3a + 6b + c + 2d) × (3a - 6b - c + 2d) = (3a - 6b + c - 2d) × (3a + 6b - c - 2d)
⇒ (3a + 6b + c + 2d)/(3a - 6b + c - 2d) = (3a + 6b - c - 2d)/(3a - 6b - c + 2d)
⇒ (3a + c) + (6b + 2d)/(3a + c) - (6b + 2d) = (3a - c) + (6b - 2d)/(3a - c) - (6b - 2d)
⇒ (3a + c)/(6b + 2d) = (3a - c)/(6b - 2d)
⇒ (3a + c)/(3a - c) = (6b + 2d)/(6b - 2d)
⇒ 3a/c = 6b/2d
⇒ a/c = b/d
⇒ ad = bc
∴ The correct option is 3 which is ad = bc.
Last updated on May 29, 2025
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