If one cubic metre of ice weighs 720 kg, then the weight of a cuboidal block of ice 50 cm in length is :

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  1. 75
  2. 80
  3. 85
  4. 90

Answer (Detailed Solution Below)

Option 4 : 90
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Detailed Solution

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Given:

Density of ice = 720 kg/m3

Length of the cuboidal block = 50 cm = 0.5 m

Formula Used:

Weight of the block = Density × Volume

Volume of the cuboidal block = Length × Breadth × Height

Calculation:

Assume the breadth and height of the cuboidal block are equal, say x meters.

Volume of the block = 0.5 × x × x = 0.5x2

Weight = 720 × 0.5x2

Given that the weight of the cuboidal block is 90 kg:

⇒ 720 × 0.5x2 = 90

⇒ 360x2 = 90

⇒ x2 = 90 / 360

⇒ x2 = 0.25

⇒ x = √0.25 = 0.5 m

So, the dimensions of the cuboidal block are:

Length = 0.5 m, Breadth = 0.5 m, Height = 0.5 m

Weight of the block = Density × Volume

Volume = 0.5 × 0.5 × 0.5 = 0.125 m3

Weight = 720 × 0.125 = 90 kg

The weight of the cuboidal block is 90 kg (Correct Option: 4).

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