Question
Download Solution PDFIn a dihybrid cross between two heterozygous fruit flies with brown bodies and red eyes (BbEe X BbEe), what will be the probability of getting BBEE genotype?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFKey Points
- The probability of getting a BBEE genotype in a dihybrid cross between two heterozygous fruit flies (BbEe X BbEe) is 1/16.
- Each parent can produce four types of gametes: BE, Be, bE, and be, with equal probability (1/4 each).
- To obtain the BBEE genotype, the offspring must receive the B and E alleles from both parents.
- The probability of getting BB from Bb X Bb cross is 1/4, and the probability of getting EE from Ee X Ee cross is also 1/4.
- Therefore, the combined probability of getting BBEE is (1/4) * (1/4) = 1/16.
Additional Information
- Mendelian inheritance explains how traits are passed from parents to offspring through genes.
- A dihybrid cross involves two pairs of contrasting traits, and the offspring of such a cross are termed dihybrids.
- In a dihybrid cross, the law of independent assortment states that alleles of different genes assort independently of one another during gamete formation.
- Understanding the principles of Mendelian genetics is crucial for studying inheritance patterns and predicting genetic outcomes.
Last updated on May 28, 2025
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