In case of max power transfer voltage drop across RL is:

F2 Savita Engineering 20-4-22 D28

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NBCC JE Electrical 29 Oct 2017 Official Paper
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  1. 5 Volts
  2. 10 Volts
  3. 2 Volts
  4. 2.5 Volts

Answer (Detailed Solution Below)

Option 4 : 2.5 Volts
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Detailed Solution

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Concept:

Maximum power transfer theorem(MPPT)

Condition for maximum power:

RL = Rth

Maximum power across load during MPPT:

Pmax = \( {(V_{th})^2 \over 4 R_{th}}\)

Where Vth = Thevenin voltage

Rth = Equivalent resistance from load terminal or Thevenin's resistance

Calculation:

During MPPT:

RL = Rth

So, the modified diagram is given below:

F2 Savita Engineering 20-4-22 D29

Applying voltage division rule across RL:

\(V_L = V\times {R_L \over R_L+2}\)

\(V_L = 5\times {2\over 2+2}\)

VL = 2.5 volts

Shortcut Trick  During MPPT voltage across the load is always half the value of the supply voltage.

\(V_L= {V_S \over 2}\)

\(V_L= {5\over 2}\)

VL = 2.5 volts

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