Question
Download Solution PDFMother told her daughter, "Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be". Find the present ages of the mother and the daughter, respectively.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation :
Let the age of mother be x and age of daughter by y.
According to question ,
⇒ x - 7 = 7(y - 7)
⇒ x - 7 = 7y - 49
⇒ x - 7y = - 42 -------(1)
And,
⇒ x + 3 = 3(y + 3)
⇒ x + 3 = 3y + 9
⇒ x - 3y = 6 --------(2)
Now subtracting eq(2) from eq(1) :
⇒ 4y = 48
⇒ y = 12
Putting value of y in eq(2) :
⇒ x - 36 = 6
⇒ x = 42
∴ The correct answer is 42, 12.
Last updated on Jun 13, 2025
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