आयताकृती कार्पेटचे क्षेत्रफळ 120 मीटर 2 आणि परिमिती 46 मीटर असते. त्याच्या कर्णाची लांबी शोधा.

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RRB JE 29 May 2019 (Shift 3) CBT 1 Official Paper
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  1. 15 मी
  2. 20 मी
  3. 17 मी
  4. 16 मी

Answer (Detailed Solution Below)

Option 3 : 17 मी
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दिले:

आयताकृती चटईचे क्षेत्रफळ = 120 मी 2

परिमिती = 46 मी

वापरलेले सूत्र:

आयताचे क्षेत्रफळ = l × b

आयताची परिमिती = 2(l + b)

आयताच्या कर्णाची लांबी = d = √(l 2 + b 2 )

कुठे,

l = आयताची लांबी

b = आयताची रुंदी

गणना:

आयताची परिमिती = 2(l + b)

⇒ 2(l + b) = 46

⇒ l + b = 23 ----(i)

आयताचे क्षेत्रफळ = l × b

⇒ l × b = 120

⇒ l = 120/b

l चे मूल्य eq मध्ये टाकणे. (i),

(120/b) + b = 23

⇒ 120 + b 2 = 23b

⇒ b 2 - 23b + 120 = 0

⇒ (b - 8)(b - 15) = 0

⇒ b = 8, 15

b = 8 m विचारात घेतल्यास, l = 23 - 8 = 15 m

कर्णाची लांबी, d = √(l 2 + b 2 )

⇒ d = √(8 2 + 15 2 )

⇒ d = √289

⇒ d = 17 मी

∴ त्याच्या कर्णाची लांबी 17 मीटर आहे.

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