शेजारच्या आकृतीत AB || CD आणि CD || EF. तसेच, EA ⊥ AB. जर ∠BGD = 62°, तर w चे मूल्य आहे:

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RRB Group D 1 Sept 2022 Shift 1 Official Paper
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  1. 28°
  2. 62°
  3. 108°
  4. 118°

Answer (Detailed Solution Below)

Option 1 : 28°
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RRB Group D Full Test 1
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Detailed Solution

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दिलेल्याप्रमाणे:

येथे AB || CD , CD || EF आणि EA ⊥ AB.

म्हणून FE⊥ EA

BGE ही तिरपी रेषा आहे.

∠BGD = 62°

∠GEC = w

वापरलेली संकल्पना:

  • समांतर रेषा म्हणजे अशा रेषा ज्या एकाच समतलावर असतात परंतु कधीही भेटत नाहीत.
  • तिरपी रेषा दोन रेषा कापते जी रेषा आहे जी दोन्ही समांतर रेषांमधून जाते.
  • पूरक कोन हे दोन कोन असतात ज्याची बेरीज 90° असते. एक सामान्य केस म्हणजे जेव्हा ते काटकोन बनवतात.
  • तिरपी रेषा जेव्हा दोन सरळ रेषांवर कापते तेव्हा तयार होणारे कोन संगत कोन म्हणून ओळखले जातात ते समान कोन असतात.

गणना:

येथे ओळ FE || DC आणि लाइन BGE ही तिरपी रेषा आहे.

⇒∠GEF=∠BGD (संगत कोन)

⇒∠GEF = 62°

दिलेली रेषा FE ⊥ EA,

⇒∠EFA = 90° (लंबकोन 90° आहे)

⇒∠FEG + ∠GEC =90°

⇒ 62° + ∠GEC =90°

⇒ ∠GEC =28°

म्हणून, w चे मूल्य 28° आहे.

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