Question
Download Solution PDFसमलंब चौकोन ABCD मध्ये, ∠BAE = 30°, ∠CDF = 45°, BC = 6 सेमी आणि AB = 12 सेमी आहे. ABCD चे क्षेत्रफळ शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFΔABE मध्ये,
⇒ cos30° = AE/AB
⇒ AE = 6√3 सेमी
⇒ sin30° = BE/AB
⇒ BE = 6 सेमी
ΔCFD मध्ये,
⇒ tan45° = CF/FD
⇒ FD = 6 सेमी [∵ BE = CF = 6 सेमी]
⇒ AD = AE + EF + FD
⇒ AD = 6√3 + 6 + 6 सेमी
⇒ AD = 12 + 6√3 सेमी
⇒ समलंब चौकोनाचे क्षेत्रफळ = 1/2 x (समांतर बाजूंची बेरीज) x उंची
⇒ समलंब चौकोनाचे क्षेत्रफळ = 1/2 x (BC + AD) x BE
∴ समलंब चौकोनाचे क्षेत्रफळ = 1/2 x (12 + 6√3 + 6) x 6 = 18(3 + √3) सेमी2
Last updated on Jun 13, 2025
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