Question
Download Solution PDFगोलार्धाची त्रिज्या 21 सेमी आहे. त्याचे आकारमान (सेमी3 मध्ये) किती असेल?
(π = 22/7 वापरा)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेली माहिती:
गोलार्धाची त्रिज्या (r) = 21 सेमी
संकल्पना किंवा सूत्र:
गोलार्धाचे घनफळ = 2/3πr3
गणना:
सूत्रात दिलेली मूल्ये बदला
⇒ आकारमान = 2/3 × 22/7 × 213 = 19404 सेमी3
म्हणून, गोलार्धाचे घनफळ 19404 सेमी3 आहे.
Last updated on Jul 8, 2025
-> The Staff Selection Commission released the SSC GD 2025 Answer Key on 26th June 2025 on the official website.
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