వృత్తం యొక్క వ్యాసార్థం 10 సెం.మీ. PQ మరియు PR లు వృత్తానికి రెండు స్పర్శరేఖలు మరియు ∠QOR = 120°, అప్పుడు, (PQ + PR + QR) యొక్క విలువ ఎంత?

Answer (Detailed Solution Below)

Option 2 :
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SSC CGL Tier 1 2025 Full Test - 01
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Detailed Solution

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ఇవ్వబడినవి , ∠QOR = 120°

అప్పుడు , ∠QOP = ∠ROP = 60°

∠OQP = ∠ORP = 90°

⇒ ∠QPO = ∠RPO = 30°

OQ = OR = 10 cm

∴ 

⇒ 

⇒ 1/2 = 10/OP

⇒ OP = 20 cm

∴ 

⇒ 

⇒ 

∴ 

మనకు ΔOQP యొక్క వైశాల్యం తెలుసు = 

⇒ 

⇒ 

 సెం.మీ.

∴ QR = 2 × KQ = 2 × 5√3 = 10√3 సెం.మీ.
ప్రశ్న ప్రకారం

 (PQ + PR + QR) యొక్క విలువ  = 

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