Question
Download Solution PDFవృత్తం యొక్క వ్యాసార్థం 10 సెం.మీ. PQ మరియు PR లు వృత్తానికి రెండు స్పర్శరేఖలు మరియు ∠QOR = 120°, అప్పుడు, (PQ + PR + QR) యొక్క విలువ ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇవ్వబడినవి , ∠QOR = 120°
అప్పుడు , ∠QOP = ∠ROP = 60°
∠OQP = ∠ORP = 90°
⇒ ∠QPO = ∠RPO = 30°
OQ = OR = 10 cm
∴
⇒
⇒ 1/2 = 10/OP
⇒ OP = 20 cm
∴
⇒
⇒
∴
మనకు ΔOQP యొక్క వైశాల్యం తెలుసు =
⇒
⇒
⇒
∴ QR = 2 × KQ = 2 × 5√3 = 10√3 సెం.మీ.
ప్రశ్న ప్రకారం
(PQ + PR + QR) యొక్క విలువ =
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