The direction of induced electric current is given by-

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  1. Fleming's right hand rule
  2. Fleming's left hand rule
  3. Ampere's law
  4. Right hand thumb rule

Answer (Detailed Solution Below)

Option 1 : Fleming's right hand rule
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The correct answer is Flemming's right-hand rule.

Key Points

Fleming's right-hand rule :

  • If we extend the forefinger, middle finger, and thumb of our right-hand perpendicular to each other as shown in the figure, and the thumb pointing towards the conductor's motion and the forefinger pointing towards the magnetic field direction, the middle finger gives us the direction of the induced current flowing in the circuit.

Flemming's right-hand rule:

When we arrange three fingers (point, middle, and thumb) as such all three are perpendicular to each other. Then,

  • The pointer finger points in the direction of the magnetic field.
  • The middle finger points in the direction of the induced current.
  • The thumb points in the direction of the motion of the conductor relative to the magnetic field.

 

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Thus, the direction of induced current in a coil is determined by using Flemming's right-hand rule.

Additional Information

Fleming's left-hand rule:

  • Stretch the thumb and the first two fingers of the left hand mutually perpendicular to each other.
  • If the forefinger points in the direction of the magnetic field, the central finger in the direction of the current, then the thumb gives the direction of the force on the charged particle.

Right-hand thumb rule:

  • When we take our right-hand and stretch the forefinger, middle finger, and thumb at right angles to each other.
  • Then the forefinger is along in the direction of the magnetic field, the thumb indicates the direction of motion or applied force, then the middle finger will show the direction of the induced current.

Ampere's law

  • Ampere’s Circuital Law states that the integrated magnetic field B along an imaginary closed path is equal to the multiplication of net electricity current enclosed inside this path and permeability of the medium.

\(\oint \overrightarrow{B}.\overrightarrow{dl} = μ _{0} I\)

where is B is the magnetic field μ0 magnetic permeability, I is current enclosed, dl is the length.

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