The speed of the crankshaft is found to vary between 120 r.p.m. and 150 r.p.m. during one cycle of operation. What is the coefficient of fluctuation of speed?

This question was previously asked in
ESE Mechanical 2016 Paper 2: Official Paper
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  1. 0.40
  2. 0.31
  3. 0.22
  4. 0.13

Answer (Detailed Solution Below)

Option 3 : 0.22
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Detailed Solution

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Concept:

Maximum Fluctuation of Speed:

The difference between the maximum and minimum speeds during a cycle is called the maximum fluctuation of speed i.e. (N1 - N2).

Coefficient of Fluctuation of Speed (Cs):

The ratio of the maximum fluctuation of speed to the mean speed is called the coefficient of fluctuation of speed.

\({C_s} = \;\frac{{{N_1} - \;{N_2}}}{N} = \;\frac{{2\left( {{N_1} - \;{N_2}} \right)}}{{{N_1} + \;{N_2}}}\)

N = Mean speed in r.p.m. \(= \frac{{{N_1} + \;{N_2}}}{2}\)

Coefficient of steadiness (m):

The reciprocal of the coefficient of fluctuation of speed is known as the coefficient of steadiness.

\(\begin{array}{l} m = \frac{1}{{Coeff.\;of\;fluctuation\;of\;speed}}\\ = \frac{{{N_{mean}}}}{{{N_{max}} - {N_{min}}}} = \frac{{{N_1} + \;{N_2}}}{{2\left( {{N_1} - {N_2}} \right)}} \end{array}\)

Calculation:

Given:

N1 = 150 rpm and N2 = 120 rpm

N  = Mean speed in r.p.m. \(= \frac{{{N_1} + \;{N_2}}}{2}=\frac{{{120} + \;{150}}}{2} =135\ rpm\)

Maximum fluctuation of speed = 150 - 120 = 30 rpm

and \({C_s} = \;\frac{{{N_1} - \;{N_2}}}{N} =\frac{30}{135}\)

∴ CS = 0.22.

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