What is x in the following program?

#include < stdio.h >

int main ( )

{typedef (* (*arrfptr [3]) ( ) ) [10];

arrfptr x;

return 0 ;

} 

The correct answer is x is an array of three function pointer

Key PointsThe given program declares an array of three function pointers named x. Each function pointer is of type (* (*arrfptr [3]) ( ) ) [10].

      typedef (* (*arrfptr[3])()) [10];

This declares arrfptr as an array of three pointers to functions with no parameters (specified by ()), and each function returns a pointer to an array of 10 elements. So, the correct answer is: x is an array of three function pointers

Additional InformationAn array of pointers in C is essentially an array where each element is a pointer. This allows you to create an ordered collection of pointers, and each pointer can point to a different location in memory. The declaration of an array of pointers involves specifying the type of the elements that the pointers will point to.