যদি \(\rm \frac{kk\cot^230^\circ}{1+\cot^2 30^{\circ}}\) = sin²60° + 4 tan²45° - cosec²60°, তাহলে k এর মান (দুই দশমিক স্থানে সঠিক) হল:

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Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 03 Dec 2022 Shift 3)

Answer 1

প্রদত্ত:

\(\rm \frac{kk\cot^230^\circ}{1+\cot^2 30^{\circ}}\) = sin260° + 4 tan245° - cosec260°

অনুসৃত ধারণা:

Trigo

গণনা:

\(\rm \frac{kk\cot^230^\circ}{1+\cot^2 30^{\circ}}\) = sin260° + 4 tan245° - cosec260°

⇒ \(k \frac {1 - 3}{1 + 3}\) = 3/4 + 4 x 1 - 4/3

⇒ \(\frac {-k}{2}\) = 41/12

⇒ k = -41/6

⇒ k ≈ -6.83

∴ k এর মান হল -6.83

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