Question
Download Solution PDFConsider the following statements:
1. (Electric or magnetic) field must have two orthogonal linear components.
2. The two components must have the same magnitude.
3. The two components must have a time-phase difference of odd multiples of 90°
Which of these are the necessary and sufficient conditions for a time-harmonic wave to be circularly polarized at a given point in space ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Polarization:
|
Linear Polarization |
Circular Polarization |
Elliptical Polarization |
|
E(z, t) = Ex + Ey |
E(z, t) = Ex + J Ey |
E(z, t) = Ex + J Ey |
|
Phase difference δ = 2nπ Where n = 0, 1, 2, … |
Phase difference \(\left( \delta \right) = \left( {2n + 1} \right)\frac{\pi }{2}\) Where, n = 0, 1, 2 …. |
Phase difference \(\left( \delta \right) = \left( {2n + 1} \right)\frac{\pi }{2}\) n = 0, 1, 2, … |
|
|
-|Ex| = |Ey| |
|Ex| ≠ Ey |
Analysis:
From the table for circular polarization –
(i) Electric/Magnetic field has two orthogonal linear components (Ex and Ey)
(ii) two components have the same magnitudes |Ex| = |Ey|
(iii) Phase difference \(\left( \delta \right) = \left( {2n + 1} \right)\frac{\pi }{2}\) n = 0, 1, 2 ….
i.e. odd multiple of 90°
So all statements are correct.
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