Question
Download Solution PDFIf skin depth of a conductor with frequency f Hz is d, what will be the new skin depth if the frequency increased to 4f :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Skin depth (δ) is the distance into a conductor at which the current density falls to 1/e of its value at the surface due to the skin effect in AC systems.
The formula gives it: \( \delta = \sqrt{\frac{2}{\omega \mu \sigma}} \)
Where,
- ω = 2πf (angular frequency)
- μ = permeability of the material
- σ = conductivity of the material
Explanation:
Since \( \delta \propto \frac{1}{\sqrt{f}} \)Skin depth is inversely proportional to the square root of the frequency.
If the frequency increases from f to 4f, then:
\( \delta_{\text{new}} = \frac{\delta}{\sqrt{4}} = \frac{\delta}{2} \)
Correct Option:
The new skin depth is: d/2
Correct Answer: 3) d/2
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