यदि (a - 18)2 + (b - 12)2 + (c - 6)2 = 0 है, तो (a + b + c)1/2 का मान ज्ञात कीजिए।

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SSC CPO 2024 Official Paper-I (Held On: 28 Jun, 2024 Shift 2)
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  1. ±3
  2. ±2
  3. ±4
  4. ±6

Answer (Detailed Solution Below)

Option 4 : ±6
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SSC CPO : General Intelligence & Reasoning Sectional Test 1
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दिया गया है:

(a - 18)2 + (b - 12)2 + (c - 6)2 = 0, तो (a + b + c)1/2 का मान ज्ञात करना है।

प्रयुक्त अवधारणा:

यदि (a - x)2 + (b - y)2 + (c - z)2 = 0, तो a = x, b = y और c = z

गणना:

(a - 18)2 + (b - 12)2 + (c - 6)2 = 0,

a = 18, b =12, और c = 6

(a + b + c)1/2 = (18+ 12 + 6)1/2

±6

∴ सही उत्तर ±6 है।

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