In a hexagonal nut, width across flats by the approximate standard method is ______ (where D = nominal diameter).

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  1. 1.0 × D + 3 mm

  2. 2 × D mm
  3. (1.5 × D) + 3 mm

  4. 4 × D mm

Answer (Detailed Solution Below)

Option 3 :

(1.5 × D) + 3 mm

Detailed Solution

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Explanation:

Standard conventional proportions may be considered while drawing a hexagonal nut:

  • ·    Width of the nut across the flat surface (known as size across flat) = (1.5 × D) + 3 mm
  • ·    The diameter of the nut = D in mm
  • ·    The thickness of the nut = (0.8 × D) to D
  • ·    The radius of front chamfer = 1.5 × D
  • ·    The angle of chamfer = 30°
  • ·     Depth of cut = 0.61 × P​

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