Question
Download Solution PDF8x + 3y = 24, 2x + 8 = y आणि x-अक्षाच्या आलेखांनी तयार केलेल्या त्रिकोणाचे क्षेत्रफळ (चौ. एककांमध्ये) आहे:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
8x + 3y = 24, 2x + 8 = y आणि x-अक्ष
वापरलेले सूत्र:
त्रिकोणाचे क्षेत्रफळ = 1/2 × पाया × उंची
8x + 3y = 24, 2x + 8 = y या दोन रेषांच्या छेदनबिंदूचा Y समन्वय त्रिकोणाची उंची देतो.
8x + 3y = 24, 2x + 8 = y रेषांच्या x अंतरच्छेद मधील फरक त्रिकोणाचा पाया देतो
गणना:
8x + 3y = 24, 2x + 8 = y साठी छेदनबिंदू शोधण्यासाठी एक समीकरण दुसऱ्यामध्ये ठेवा
⇒ 8x + 3(2x + 8) = 24
⇒ 14x = 0
⇒ x = 0
⇒ y = 2×0 + 8 = 8
⇒ त्रिकोणाची उंची = 8
8x + 3y = 24, 2x + 8 = y X शोधण्यासाठी y – छेदन y = 0 ठेवा
⇒ 8x + 3×0 = 24
⇒ x1 = 3
⇒ 2x + 8 = 0
⇒ x2 = -4
त्यांचा फरक पाया = 3 – (-4) = 7 आहे
∴ त्रिकोणाचे क्षेत्रफळ = 8 × 7/2 = 28
Last updated on Jun 13, 2025
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