Question
Download Solution PDF8 సెంటీమీటర్ల వ్యాసార్థం యొక్క రెండు సమాన వృత్తాలు ఒకదానికొకటి కేంద్రం వద్ద ఖండిస్తాయి. సాధారణ సరళరేఖ యొక్క పొడవు:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చినది:
వృత్తాల వ్యాసార్థం 8 సెం.మీ
లెక్కింపు:
రేఖాచిత్రం ప్రకారం,
AD = DB
O1 O2 = 8
మళ్ళీ O1 A = O2 A = 8 [వృత్తం యొక్క వ్యాసార్థం]
∠ADO1 = 90°
O1 D = O2 D = 4
AD = √(64 - 16)
⇒ √48 = 4√3
AB = 2 × 4√3 = 8√3
∴ సాధారణ తీగ యొక్క పొడవు 8√3 సెం.మీ
Last updated on Jun 2, 2025
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