Question
Download Solution PDFThe total number of men, women and children working in a factory is 18. They earn Rs 4000 in a day. If the sum of the wages of all men, all women and all children is in the ratio of 18 : 10 : 12 and if the wages of an individual man, woman and child is in the ratio 6 : 5 : 3, then how much a child earns in a day?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Total number of men, women, and children = 18
Total wages in a day = Rs. 4000
Sum of wages ratio (men : women : children) = 18 : 10 : 12
Individual wage ratio (man : woman : child) = 6 : 5 : 3
Formula Used:
Total wages = (Number of men × Wage of one man) + (Number of women × Wage of one woman) + (Number of children × Wage of one child)
Calculation:
Let the number of men, women, and children be m, w, and c respectively.
m + w + c = 18 ...(1)
Let the wages of one man, woman, and child be 6x, 5x, and 3x respectively.
The total wages are distributed in the ratio 18 : 10 : 12.
Total wages = Rs. 4000
Wages of all men = (18 / (18 + 10 + 12)) × 4000 = (18 / 40) × 4000 = Rs. 1800
Wages of all women = (10 / 40) × 4000 = Rs. 1000
Wages of all children = (12 / 40) × 4000 = Rs. 1200
For men: Total wages of all men = m × 6x = 1800 ...(2)
For women: Total wages of all women = w × 5x = 1000 ...(3)
For children: Total wages of all children = c × 3x = 1200 ...(4)
From equation (2):
⇒ m × 6x = 1800
⇒ m × x = 300 ...(5)
From equation (3):
⇒ w × 5x = 1000
⇒ w × x = 200 ...(6)
From equation (4):
⇒ c × 3x = 1200
⇒ c × x = 400 ...(7)
From equations (5), (6), and (7):
m = 300 / x, w = 200 / x, c = 400 / x
Substitute these values into equation (1):
⇒ (300 / x) + (200 / x) + (400 / x) = 18
⇒ (300 + 200 + 400) / x = 18
⇒ 900 / x = 18
⇒ x = 900 / 18
⇒ x = 50
Wage of one child = 3x
⇒ Wage of one child = 3 × 50
⇒ Wage of one child = Rs. 150
The wage of one child in a day is Rs. 150.
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